The pressure lost along an air pipe rises with the flow to the power 1.75 and falls with the inside diameter to the power 4.75, so a small increase in bore cuts the loss sharply. At 235 L/min of free air over 20 m, a smooth 8 mm bore loses about 0.253 bar, a 12 mm bore about 0.037 bar and a 20 mm bore about 0.0033 bar.

Choosing the bore of an air line by computing the pressure it loses at the flow it carries, instead of by a rule of thumb.

The Method: Darcy-Weisbach With a Smooth-Pipe Friction Factor

Pressure drop along a pipe is

Δp = f x (L / D) x (ρ x v² / 2)

with f the friction factor, L the length, D the inside diameter, ρ the air density at line pressure and v the velocity. For smooth pipe and Reynolds numbers below about 10⁵, the Blasius formula gives f = 0.316 x Re^-0.25, where Re = ρ x v x D / μ. These formulas, and air’s viscosity of 1.8 x 10⁻⁵ Pa·s, are recalled from fluid-mechanics texts and not from this corpus; the same Darcy-Weisbach structure appears in the corpus’s water pipe pages (Friction Losses).

Worked Example: 235 L/min Through 20 m of 12 mm Pipe

Supply at 7 bar gauge (8 bar absolute) and 20 °C. Free-air density 1.204 kg/m³.

  1. Mass flow = 1.204 x (0.235 / 60) = 4.716 x 10⁻³ kg/s
  2. Air density at 8 bar absolute = 8 x 101,325 / (287.05 x 293.15) = 9.63 kg/m³
  3. Pipe area = π / 4 x 0.012² = 1.131 x 10⁻⁴ m²; velocity = 4.716 x 10⁻³ / (9.63 x 1.131 x 10⁻⁴) = 4.33 m/s
  4. Re = 9.63 x 4.33 x 0.012 / 1.8 x 10⁻⁵ = 27,800
  5. f = 0.316 x 27,800^-0.25 = 0.0245
  6. Δp = 0.0245 x (20 / 0.012) x (9.63 x 4.33² / 2) = 0.0245 x 1,667 x 90.3 = 3,690 Pa = 0.037 bar

Results for Three Bores and Three Flows (20 m, Smooth Pipe)

Free air8 mm inside diameter12 mm20 mm
150 L/min0.115 bar (6.2 m/s)0.017 bar0.0015 bar
235 L/min0.253 bar (9.7 m/s)0.037 bar (4.3 m/s)0.0033 bar (1.6 m/s)
500 L/min0.947 bar (20.7 m/s)0.138 bar0.012 bar

The Scaling Law Replaces the Table

Velocity goes as flow over diameter squared, f as (flow / diameter)^-0.25, and the loss as f x velocity² / diameter, so

Δp is proportional to Q^1.75 x D^-4.75 (density held constant)

Checks against the table: going from 8 mm to 12 mm should cut the loss by (12 / 8)^4.75 = 6.9, and 0.253 / 0.037 = 6.9. Going from 12 mm to 20 mm: (20 / 12)^4.75 = 11.3, and 0.037 / 0.0033 = 11. Raising flow from 235 to 500 L/min multiplies the loss by (500 / 235)^1.75 = 3.75, and 0.947 / 0.253 = 3.75. The carrier’s rule, to oversize pipe because lost pressure is expensive, follows directly: a half-again bore cuts the loss seven-fold.

The carrier’s own figures do not reproduce. The carrier lists drops of 0.3 bar for 12 mm, 1.2 bar for 8 mm and 0.05 bar for 20 mm at “15 L/min” over 20 m. At 15 L/min the calculation gives about 0.002 bar for 8 mm, and the three figures are not in the 6.9 and 11 ratios the scaling law requires. Use the table above.

Limits of This Calculation

  • The pipe is assumed smooth. Corroded or scaled steel loses more.
  • Fittings, elbows, valves and couplers add losses, not included here.
  • Density is taken at the supply pressure, a good approximation while the drop is small against the line pressure; at 0.947 bar it is already a rough guide.
  • The Blasius formula holds below Re of about 10⁵, which covers all the cases above.

Common Mistakes

  • Using nominal pipe sizes as inside diameters. An 8 mm bore is the inside diameter, not the label on a pipe.
  • Sizing for average flow. Size for the largest flow that runs at once.
  • Adding a tool without rechecking the main. The loss goes as the flow to the 1.75 power.

Safety

Starved tools tempt people to raise the pressure

When a long, narrow line leaves a tool short of pressure, the temptation is to raise the regulator or the relief setting. Do not: the pipe, hose and fittings were chosen against the relief setting, and the weakest part is the limit (Piping and Fittings). Fix the bore instead. A calculated pressure drop is not a pressure rating; each part still needs its own.

What’s Next